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1. |
Speed of a body in motion is doubled. Its kinetic energy is now …………. Times the original kinetic energy. |
Answer» two Now, doubling its speed, `E_(k).=(1)/(2)m(2v)^(2)` `=(1)/(2)mv^(2)xx4=4E_(k)` Thus, the kinetic energy of the OBJECT becomes four TIMES. |
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