1.

Speed of a body in motion is doubled. Its kinetic energy is now …………. Times the original kinetic energy.

Answer»

two
three
four
half

SOLUTION :kinetic energy `E_(k)=(1)/(2)mv^(2)`
Now, doubling its speed,
`E_(k).=(1)/(2)m(2v)^(2)`
`=(1)/(2)mv^(2)xx4=4E_(k)`
Thus, the kinetic energy of the OBJECT becomes four TIMES.


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