1.

`sqrt((1-sintheta)/(1+sintheta))={sectheta-tantheta ,` if `-pi/2ltthetaltpi/2` and `-sectheta+tantheta`,` pi/2ltthetalt(3pi)/ 2`

Answer» `sqrt((1-sintheta)/(1+sintheta))sqrt((1-sintheta)/(1+sintheta))`
`sqrt((1-sintheta)^2/(1-sin^2theta))`
`sqrt((1-sintheta)^2/cos^2theta)`
`sqrt((sectheta-tantheta)^2`
`sectheta-tantheta,-pi/2ltxltpi/2`
`tantheta-secctheta,pi/2ltxlt3/2pi`.


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