1.

`sqrt(3)cossec2 0^0-sec2 0^0`A. 2B. 2 sin `20^(@)//sin 40^(@)`C. 4D. `4 sin 20^(@)//sin40^(@)`

Answer» Correct Answer - C
Given expression =
`sqrt(3) cosec 20^(@)-sec 20^(@) = tan 60^(@) cosec 20^(@) - sec 20^(@)`
`=(sin 60^(@) cos 20^(@) - cos60^(@).sin20^(@))/(cos60^(@).sin20^(@)cos20^(@))`
`=(sin(60^(@)-20^(@)))/(cos60^(@).sin20^(@).cos20^(@)) = (sin 40^(@))/((1)/(2).sin20^(@) cos20^(@))`
`=(2sin20^(@) cos 20^(@))/((1)/(2)sin 20^(@) cos 20^(@)) = 4`


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