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Starting with a sample of pure `.^66 Cu, 7//8` of it decays into `Zn` in `15 min`. The corresponding half-life is.A. 10 minB. 5 minC. 15 minD. `7 (1)/(2) min` |
Answer» Correct Answer - B (b) `N = N_0 (1 - e^(-lamda t))` `rArr (N_0 - N)/(N_0) = e^(-lamda t)` `:. (1)/(8) = e^(-lamda t)` `rArr 8 = e^(lamda t)` `rArr 3 1n 2 = lamda t` `rArr lamda = (3 xx 0.693)/(15)` Half-life period `t_(1//2) = (0.693)/(3 xx 0.693) xx 15` `t_(1//2) = 5 min`. |
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