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Statement -1 : Determinant of a skew-symmetric matrix of order 3 is zero. Statement -2 : For any matrix A, Det `(A) = "Det"(A^(T)) and "Det" (-A) = - "Det" (A)` where Det (B) denotes the determinant of matrix B. Then,A. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 6B. Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 6C. Statement 1 is true, Statement 2 is FalseD. Statement 1 is False, Statement 2 is true |
Answer» Correct Answer - C Let A be a skew - symmetric matrix of order 3 Then, `A^(T) = -A` `rArr Det (A^(T)) = Det (-A)` `rArr Det (A) = (-1)^(3) Det (A)` `rArr Det(A) = - Det(A)` `rArr 2Det(A) = 0` `rArr Det (A) = 0` So, statement -1 is true. For any square matrix of order n, we have `Det(A^(T)) = Det(A) and Det(-A) = (-1)^(n) Det(A)` So, statement -2 is not true |
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