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Statement -1 : Determinant of a skew-symmetric matrix of order 3 is zero. Statement -2 : For any matrix A, Det `(A) = "Det"(A^(T)) and "Det" (-A) = - "Det" (A)` where Det (B) denotes the determinant of matrix B. Then,A. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 6B. Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 6C. Statement 1 is true, Statement 2 is FalseD. Statement 1 is False, Statement 2 is true

Answer» Correct Answer - C
Let A be a skew - symmetric matrix of order 3
Then,
`A^(T) = -A`
`rArr Det (A^(T)) = Det (-A)`
`rArr Det (A) = (-1)^(3) Det (A)`
`rArr Det(A) = - Det(A)`
`rArr 2Det(A) = 0`
`rArr Det (A) = 0`
So, statement -1 is true.
For any square matrix of order n, we have
`Det(A^(T)) = Det(A) and Det(-A) = (-1)^(n) Det(A)`
So, statement -2 is not true


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