1.

Study the following electric circuit and calculate the potential difference across5 Omegaresistor.

Answer»

Solution :V=IR
R = 3+4+5 `=12 Omega`
`3=Ixx12`
`I = (3)/(12) =(1)/(4)` Ampere ,
Potential difference across `5 Omega` RESISTOR .
V=IR
`V= (1)/(4) XX5`
`= (5)/(4) V ` or 1.25 V


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