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Study the following electric circuit and calculate the potential difference across5 Omegaresistor. |
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Answer» Solution :V=IR R = 3+4+5 `=12 Omega` `3=Ixx12` `I = (3)/(12) =(1)/(4)` Ampere , Potential difference across `5 Omega` RESISTOR . V=IR `V= (1)/(4) XX5` `= (5)/(4) V ` or 1.25 V |
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