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Study the following electric circuit (i) Calculate the current flowing in the circuit and (ii) Calculate the potential difference across 10 Omegaresistor |
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Answer» Solution :(i) `R= R_(1)+R_(2)=10+20=30 Omega` V=3 V (i) From ohm.s V= IR `3 =I xx30 implies I = (3)/(30)= (1)/(10)` Ampere or 0.1 A (ii) Potential DIFFERENCE across `10Omega` resistor V= IR `=(1XX10)/(10 ) ` = 1 volt . |
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