1.

Successive ionisation potentials of an element 'X' are IP_(1) = 520 kJ mol^(-1), IP^(2) = 7,298 kJ mol^(-1) and IP^(3) = 10,815 kJ mol^(-1) Give the probable formulae of chloride and oxide of 'X'.

Answer»

Solution :(i) COMPARING IP values, VALENCY of X
(ii) ABRUPT change in IP value
(III) valence electronic configuration of STABLE ion
(iv) valencise of the corresponding postive and
negative radicals


Discussion

No Comment Found

Related InterviewSolutions