

InterviewSolution
Saved Bookmarks
1. |
The acticity of a sample is `64 xx 10^-5 Ci`. Its half-life is `3` days. The activity will become `5 xx 10^-6 C i` after.A. 12 daysB. 7 daysC. 18 daysD. 21 days |
Answer» Correct Answer - D (d) `A = A_0 ((1)/(2))^(t//T_1//2) rArr 5 xx 10^-6 = 64 xx 10^-5 ((1)/(2))^(t//3)` `(1)/(128) = ((1)/(2))^(t//3) rArr t = 21 days`. |
|