1.

The amounts of metals deposited when 965 C of electricity is passed through NaCl and AgNO_(3) solution are _____ and ____, respectively.

Answer»

23g, 108 G
11.5 g, 54g
0.23g, 1.08g
2.3g, 10.8 g

Solution :`W = (M.c.t.)/(n.96,500) or (MQ)/(n96,500)`
`W_(Na) = (23 xx 965)/(1 xx 96,500)g, W_(Ag) = (108 xx 965)/(1xx 96,500) g`
`W_(Na) = 0.23g, W_(Ag) = 1.08 g`


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