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The area of the base of a cuboidal box is 35 sq. cm and the area of one of the faces is 60 sq. cm. The numerical value of each of the dimensions of this box is an integer greater than 1. Then the volume of the cuboidal box, in cu. cm, is1). 2102). 6203). 8404). 420 |
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Answer» Now let B be the base of the cuboidal box whose area is 35 sq. cm and let A be the area of one of the FACE which is 60 sq. Cm We can see that there is a COMMON SIDE to face A and face B. ∴ We will find the factors of the area of both faces and the common number will be length of the common side ⇒ 35 = 5 × 7 ⇒ 60 = 2 × 2 × 3 × 5 Now we can see that the length of the common side = 5 cm ∴ Length of the other sides of the cuboid will be remaining factors of the area ∴ other sides are 7 and 2 × 2 × 3 i.e. 7 and 12 Now Volume of cuboid = l × b × h Where l = length, b = breadth, h = height ∴ Volume of cuboid = 5 × 7 × 12 = 420 cm3 |
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