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The atomic mass and atomic number of lead are 208 and 82. The atomic mass and atomic number of bismuth are 209 and 83. The `"neutron"//"proton"` ratio in an atomA. Higher of leadB. Higher of bismuthC. SameD. None of these |
Answer» Correct Answer - A `(n)/(p) " of " ._(82)Pb^(208) = (126)/(82) = 1.53` `(n)/(p) " of " ._(83)Bi^(209) = (126)/(83) = 1.51` |
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