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The atomic mass of `Al^(27)` is 26.9815 amu . The mass of electron is 0.0005498 amu . The rest mass energy of `Al^(27)` nucleus isA. 1862 MeVB. 25119.78 MeVC. 25113.12 MeVD. None of these |
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Answer» Correct Answer - A The mass of Al nucleus is `therefore` `m_(0)` = atomic mass - mass of total electrons = 26.974353 amu `therefore` E = `m_(0)`` xx ` 931 MeV E = 26.974353 MeV = 25113.12 MeV |
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