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The atomic mass of `B^(10)` is 10.811 amu . Find the binding energy of `B^(10)` nucleus . The mass of electron is 0.0005498 amu. The mass of proton is `m_(p)` = 1.007276 amu . The mass of neutron is `m_(n)` = 1.008665 amu.A. 186.54 MeVB. 678.932 MeVC. 378.932 MeVD. None of these |
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Answer» Correct Answer - A The mass of `B^(10)` nucleus `m_(0)` = 10.811 -` 5 xx 0.0005498` 10.808251 amu Binding energy = (5`m_(p))` + 5`m_(n)`) - mass of `B^(10)` nucleus )` xx ` 931 MeV {(` 5 xx 1.007276 + 5 xx 1.008665) - 10.808251`}931 MeV (10.079 - 10.808251)931MeV - 678.932 MeV |
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