1.

The atomic masses of He and Ne are 4 and 20 amu respectively . The value of the de Broglie wavelength of He gas at`-73.^(@)C` is 'M' times that of the de Broglie wavelength of Ne at `727.^(@)C.` M is

Answer» Correct Answer - 5
`lambda=h/sqrt(2m(KE)) " " KE prop T`
`lambda_(He)/lambda_(Ne)=sqrt((m_(Ne)KE_(Ne))/(m_(He)KE_(He)))=sqrt((20xx1000)/(4xx200))=5`


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