The atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write theelectronic configuration of each element and answer the following questions:(a) Which one of N, O and F is most electronegative and which one is least electronegative? (b) What is the number of valence electrons of F? (c) What is valency of each one of N, O and F?

The atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 res

1.	The atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write theelectronic configuration of each element and answer the following questions:(a) Which one of N, O and F is most electronegative and which one is least electronegative? (b) What is the number of valence electrons of F? (c) What is valency of each one of N, O and F?
Answer» Solution :Electronic CONFIGURATION of Nitrogen : 2,5 OXYGEN : 2,6 Fluorine : 2,7 (a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative. (b)Fluorine (F) has 7 valence electrons. (c) Valency of nitrogen is 3 and 5, valency of oxygen is 2, valency of fluorine is 1.