1.

The attenuation in dB in terms of input power (P1) and output power (P2) is?(a) log10 (P1/P2)(b) 10 log10 (P1/P2)(c) log10 (P2/P1)(d) 10 log10 (P2/P1)I had been asked this question in class test.I'm obligated to ask this question of Attenuators topic in division Filters and Attenuators of Network Theory

Answer»

Correct choice is (B) 10 log10 (P1/P2)

To elaborate: The INCREASE or DECREASE in power DUE to insertion or SUBSTITUTION of a new element in a network can be conveniently expressed in decibels or in nepers. The attenuation in dB in terms of input power (P1) and output power (P2) is Attenuation in dB = 10 log10 (P1/P2).



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