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The average osomotic pressure of human blood is 7.8 bar at `37^(@)C`. What is the concentration of an aqueous `NaCI` solution that could be used in the blood stream?A. `0.16 mol//L`B. `0.32 mol//L`C. `0.60mol//L`D. `0.45 mol//L` |
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Answer» Correct Answer - A `pi=7.8" bar ", T = 37^(@)C = 300 K` `R = 0.083L " bar " mol^(-1)K^(-1)` i = 2 for `Na^(+) Cl^(-)` `pi = (I xx n_(B)xx R xx T)/(V)` `(n_(B))/(V)= (pi)/(iRT)` `=(7.8"bar")/(2xx(0.083 L^(-1)mol^(-1)K^(-1))xx300K)` `= 0.1566 mol L^(-) = 0.16 mol/L` |
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