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The `(B.E)/(A)` for deutron and an `alpha`-particle are `X_(1)` and `X_(2)` respectively. The energy released `alpha`-particle isA. `4(X_(2)-X_(1))`B. `2(X_(2)-X_(1))`C. `4(X_(2)+X_(1))`D. `(X_(2)-X_(1))/(4)` |
Answer» Correct Answer - A | |