1.

The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ? `._1H^2 + ._1H^2 rarr ._2He^4 + Q`.A. `4(x_(1)+x_(2))`B. `4(x_(2)-x_(1))`C. `2(x_(1)+x_(2))`D. `2(x_(2)-x_(1))`

Answer» Correct Answer - B
`._(1)H^(2) +._(1)H^(2) rarr._(2)He^(4) +Q`
`Q -` value `= 4x_(2) - 4x_(1) = 4(x_(2)-x_(1))`


Discussion

No Comment Found

Related InterviewSolutions