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The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ? `._1H^2 + ._1H^2 rarr ._2He^4 + Q`.A. `4(x_1 + x_2)`B. `4(x_2 - x_1)`C. `2(x_1 + x_2)`D. `2(x_2 - x_1)` |
Answer» Correct Answer - B (b) `Q = 4 (x_2 - x_1)`. |
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