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The binding energy of `._(2)^(4)He` is 28.57 MeV. What shall be the binding energy per nucleon of this element? |
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Answer» The nucleus of `._(2)^(4)He` consists of 4 nucleons. So, Binding energy per nucleon `=("Total binding energy")/("No. of nucleons")` `=(28.57)/(4)=7.14MeV` |
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