InterviewSolution
Saved Bookmarks
| 1. |
The brakes applied to a car produce an acceleration of 6 ms^( 2) in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time. |
|
Answer» SOLUTION :Here, `a =- 6 ms ^(-2),t =2 s and v =0 ms ^(-1) v =U +at` `0= u + (-6 ms ^(-2)) xx 2s` ` or u = 12 ms ^(-1)` `s = ut + (1)/(2) at ^(2)` `= (12 ms ^(-1)) xx (2s) + (1)/(2) (- 6 ms ^(-2)) xx (2s )^(2)` `= 24 m-12 m= 12 m` Thus, the car will TRAVEL 12 m before it stops after the application of brakes. Can you now appreciate why drivers are cautioned to MAINTAIN some distance between vehicles while travelling on the road ? |
|