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The CHEical equation for the manufacture of ammonia is N_2(g)+3H_2(g) to 2NH_3(g) Calculate the amount of H_2 required to react with 28 g of N_2, completely. [Hint Molecular mass of N_2 = 28, H_2 =2]

Answer»


Answer :28 G `N_2` REQUIRES 3 MOL `H_2`3 mol `H_2` = `3times2=6g`


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