1.

The combustion of 1 mol of benzene takes place at 298 K. After combustion CO_(2) and H_(2)O are formed and 3267 kJ mol^(-1) of heat is liberated. Calculate Delta_(f) H^(0) (C_(6)H_(6)). Given: Delta_(f) H^(0) (CO_(2)) = -286kJ mol^(-1), Delta_(f) H^(0) (H_(2)O) = - 393 kJ mol^(-1)

Answer»

SOLUTION :`48.51 KJ MOL^(-1)`


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