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The correct set of four quantum number for the valence (outermost) electron of radiation `(Z = 37)` isA. `5, 0, 0, + (1)/(2)`B. `5, 1 , 0, + (1)/(2)`C. `5, 1, 1, + (1)/(2)`D. `6, 0, 0, + (1)/(2)` |
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Answer» Correct Answer - A (a) Electronic configuration of `Rb_((37))` is `1 s^2 2 s^2 2 p^6 3 s^3 3 p_3^(6)3 d^10 4 s^2 4 p^6 5 s^1` So for the valence shell electron `(5 s^1)` `n = 5, l = 0, m = 0, s = + (1)/(2)`. |
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