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The correct set of four quantum number for the valence (outermost) electron of radiation `(Z = 37)` isA. `5,0,0,+1//2`B. `5,1,0,+1//2`C. `5,1,1,+1//2`D. `6,0,0,+1//2` |
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Answer» Correct Answer - B `Rb(z = 37)` `[Kt]_(36)5s^(1)` Find the last electron `n = 5,l = 0,m = 0,s= 1//2` |
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