1.

The correct set of four quantum number for the valence (outermost) electron of radiation `(Z = 37)` isA. `5,0,0,+1//2`B. `5,1,0,+1//2`C. `5,1,1,+1//2`D. `6,0,0,+1//2`

Answer» Correct Answer - B
`Rb(z = 37)`
`[Kt]_(36)5s^(1)`
Find the last electron
`n = 5,l = 0,m = 0,s= 1//2`


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