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The current I in the circuit given below is ________(a) \(\frac{1}{4}\) A(b) \(\frac{5}{4}\) A(c) \(\frac{3}{4}\) A(d) \(\frac{1}{2}\) AThis question was addressed to me in homework.My enquiry is from Advanced Problems on Superposition Theorem in chapter Useful Theorems in Circuit Analysis of Network Theory

Answer»

Right answer is (b) \(\frac{5}{4}\) A

Explanation: Using SUPERPOSITION Theorem, we can write

I = \(\frac{24}{3+2} – \frac{72}{3+2} – \frac{3I}{3+2} \)

Or, I = 2 – \(\frac{3I}{3+2}\)

Or, I = 2 – \(\frac{3I}{5}\)

∴ I = \(\frac{5}{4}\) A.



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