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The de Broglie wavelenth of `1 mg` grain of sand blown by a `20 m s^-1` wind is :A. `3.3xx10^(-29)m`B. `3.3xx10^(-21)m`C. `3.3xx10^(-49)m`D. `3.3xx10^(-42)m` |
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Answer» Correct Answer - A `lamda=(h)/(mv)=(6.626xx10^(-34))/(1xx10^(-6)xx20)=3.313xx10^(-29)m` |
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