InterviewSolution
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InterviewSolution
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The decay constant of a radioactive substance is` 0.173 year^(-1)`. Therefore,A. Nearly `63%` of the radioactive substance will decay in `(1//0.173)` year.B. half-life of the radio active subtance is `(1//0.173)` year.C. one-forth of the radioactive substance will be left after nerarly `8` years.D. half of the substance will decay in one average life time. |
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Answer» Correct Answer - A::C Given , `lambda=0.173` `T_(1//2)=(ln2)/(lambda)=(0.693)/(0.173)~=4` Also `N_(0)-N=N_(0)e^(-lambdat)` For `t=(1)/(0.173)"year"` `N_(0)-N=(N_(0))/(e )=0.37N_(0)` |
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