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The decreasing order of energy for the electrons represented by the following sets of quantum number is : 1.`n = 4,l = 0,m = 0,s = +- 1//2`2.`n = 3,l = 1,m = 1,s = - 1//2`3.`n = 3,l = 2,m = 0,s = + 1//2`4.`n = 3,l = 0,m = 0,s = - 1//2` |
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Answer» Find `( n + l)` for each set ` For (1) ( n + l) = 4 i.e., 4s` ` For (2) ( n + l) = 4 i., e , 3 p` ` For (3) ( n+ l) =5 i.e, 3d` ` For (4) ( n + l) =3 i.e, 3s` (1) Lower is the value of `( n + l)` lower is energy level . (2) If `( n +l)` are same then orbital with lower values of ( n) possesses lower energy . `:.` Decreasing ofer of energy ` 3 gt 1 gt 2 gt 4 .` |
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