1.

The decreasing order of energy of the `3d,4s,3p,3s` orbital is :-A. `3dgt3sgt4sgt3p`B. `3sgt4sgt3pgt3d`C. `3dgt4sgt3pgt3s`D. `4sgt3dgt3sgt3p`

Answer» Correct Answer - C
The value of `l=0` to `(n-1)`
Number of electron for given value of `l=2 (2l+1)` hence `underset(l=0)overset(l=(n-1))(sum)2(2l+1)`


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