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The density (in g `mL^(-1)`) of 3.60 M sulphuric acid solution this is 29% `H_(2)SO_(4)` (molar mass =98 g `mol^(-1)`) by mass will be :A. 1.45B. 1.64C. 1.88D. 1.22 |
Answer» Correct Answer - d By definition, `3.6 M (3xx98=352.8 g) of H_(2)SO_(4)` are present in 1000 mL of solution. 29.0 g of acid are present in solution=100 g 325.8 of acid are present in soluion `((100g))/((29.0 g))xx(352.8 g)` =1216 g `"Density of solution"=("Mass of solution")/("Volume of solution")` `((1216g))/((1000mL))=`1.22 g `mol^(-1)` |
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