

InterviewSolution
Saved Bookmarks
1. |
The density `("in" g mL^(-1))` of a `3.60 M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `=98 g mol^(-1)`) by mass will be:A. `1.22`B. `1.45`C. `1.64`D. `1.88` |
Answer» Correct Answer - 1 `Density _("soln")=(mass_("soln"))/(volume_("soln"))` `3.60 M` sulphuric acid solution means that 3.6 mole `H_(2)SO_(4)` is dissolved in every `1 L (1000 mL)` of solution. Thus `mass_(H_(2)SO_(4))=(n_(H_(2)SO_(4)))("moles mass"_(H_(2)SO_(4)))` `=(3.6 mol)(98 g mol^(-1))` `=352.8 g` By definition `mass % H_(2)SO_(4)=(mass_(H_(2)SO_(4)))/(mass_(solution))xx100%` Thus `mass_(soln)=(mass H_(2)SO_(4))/(mass % H_(2)SO_(4))xx100%` `=(352.8 g)/(29%)xx100%` `=1216 g` Substituting this result, we get `"density"_(soln)=((1216 g)/(1000 mL))/("Density of soln")` `=1.216 g mL^(-1)` `=1.22 g mL^(-1)` |
|