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The density of a solution containing `13%` by mass of sulphuric acid is `1.09g//mL`. Calculate the molarity and normality of the solutionA. ` 1.445M `B. ` 14.45M `C. ` 144.5M `D. ` 0.1445M ` |
Answer» Correct Answer - A Volume of ` 100g `of the solution =` (100)/(d)` `=(100)/(1.09)mL = (100)/(1.09xx1000)` litre `(1)/(1.09xx10)` litre Numbers of moles of `H_(2)SO_(4)` in `100 g` of the solution `=(13)/(98)` Molarity `= ("No. of moles of water")/("Volume in litre")` `(13)/(98)xx(1.09xx10)/(1)=10445 M` |
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