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The depression in freezing point of `0.01 m` aqueous `CH_(3)CooH` solution is `0.02046^(@)`, `1 m` urea solution freezes at `-1.86^(@)C`. Assuming molality equal to molarity, `pH` of `CH_(3)COOH` solution isA. 2B. 3C. `3.2`D. `4.2` |
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Answer» For urea `DeltaT_(t)=K_(t)xxm` or `K_(t)=(DeltaT_(t))/(m)=(1.86)/(1)=1.86` Now for `CH_(3)COOH` `DeltaT_(t)=i K_(t)m` so `i=(0.02046)/(1.86xx0.01)=1.1` Now `i=1+alpha` so `alpha=1.1-1=0.1` Now `{:(CH_(3)COOH,hArr,CH_(3)COO^(-),+,H^(+)),(" "C,,0,,0),(C-Calpha,,Calpha,,Calpha):}` `[H^(+)]=Calpha=0.1xx0.1=0.001` so `pH=3`. |
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