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the derivative of `y=(1-x)(2-x)..........(n-x)` at `x=1` is equal to |
Answer» `(dy)/(dx)=-[(2-x)(3-x)...(n-x)+(1-x)(3-x)...(n-x)+...(1-x)(2-x)...(n-1-x)]` At x = 1, `(dy)/(dx)=-[(n-1)!+0+...+0]=(-1)(n-1)!` |
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