1.

The diagonals of a rhombus are 16 cm and 12 cm respectively. The perimeter of the rhombus is:1). 40 cm2). 42 cm3). 38 cm4). 34 cm

Answer»

Side of rhombus = ½ √(sum of SQUARES of diagonal)

Given, diagonals of a rhombus are 16 CM and 12 cm respectively.

⇒ Side $(= \FRAC{1}{2} \times \SQRT {{{16}^2} + {{12}^2}})$

⇒ Side = 10 cm

Perimeter = 4 × side = 40 cm


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