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The differnce between nth and `(n+1)` the Bohr radius of B atom is equal to be its `(n-1)` th Bohr radius .The value of n isA. `1`B. `2`C. `3`D. `4` |
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Answer» Correct Answer - D `r_n =r_1 xxn^2 , r__(n+1) = r_1 xx (n+1)^2` ` r_(n-1) = r_n (n-1)^2` `:. R_(n+1) =r_n = r_1 [n^2 + 2 n+ 1 -n^2]` ` =r_1 (2 n+1)` ` r_( n-1) = r _(n+1)^(-r_n)` ltbRgt ` :. (n-1)^2 = 2n +1` ` :. N=4`. |
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