1.

The differnce between nth and `(n+1)` the Bohr radius of B atom is equal to be its `(n-1)` th Bohr radius .The value of n isA. 1B. 2C. 3D. 4

Answer» `r_(2) prop n^(2)`
`But r_(n + 1) - r_(n) = r_(n-1)`
`(n+1)^(2) - n^(2) = (n - 1)^(2)`
`n = 4`


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