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The differnce between nth and `(n+1)` the Bohr radius of B atom is equal to be its `(n-1)` th Bohr radius .The value of n isA. 1B. 2C. 3D. 4 |
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Answer» `r_(2) prop n^(2)` `But r_(n + 1) - r_(n) = r_(n-1)` `(n+1)^(2) - n^(2) = (n - 1)^(2)` `n = 4` |
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