1.

The dimensional formula for ω in the relation y = A Sin ωt is

Answer»

`[M° L° T]`
`[M° L° T^(–1)]`
`[ML° T°]`
`[M° L^(–1) T^(–1)]`

Solution :`ωt` = Angle = DIMENSIONLESS
so DIMENSION of `ω=(1)/(t)=[M^(@)L^(@)T^(-1)]`


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