1.

The displacement of a body is proportional to t^(3), where t is time elapsed. What is the nature of acceleration - time graph of the body?

Answer»

Solution :as`s ALPHA t^(3) rArr KT^(3)`
VELOCITY, `V=(ds)/(dt)=3kt^(2)`
acceleration, `a=(dv)/(dt)=6kt`
i.e., `a alpha t`.
`rArr` motion is uniform, ACCELERATED motion, a – t graph is straight-line.


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