1.

The displacement x of a particle varies with time as x = 4t^(2) – 15t + 25. Find the position, velocity and acceleration of the particle at t = 0.

Answer»

SOLUTION :position, x = 25 m
VELOCITY `=(dx)/(dt)=8t-15`,
`t=0, v=0-15=-15 m//s`
acceleration, `a=(DV)/(dt)=8 ms^(-2)` .


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