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The displacement x of a particle varies with time as x = 4t^(2) – 15t + 25. Find the position, velocity and acceleration of the particle at t = 0. |
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Answer» SOLUTION :position, x = 25 m VELOCITY `=(dx)/(dt)=8t-15`, `t=0, v=0-15=-15 m//s` acceleration, `a=(DV)/(dt)=8 ms^(-2)` . |
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