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The e.m.f a cell is 1.5V. What is the energy provided by the cell to drive 0.5C of charge around the circuit? |
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Answer» Solution :`VAREPSILON=1.5 V" and "q=0.5C` `varepsilon= W"/"q , W= varepsilon XX q , " THEREFORE "W= 1.5xx0.5=0.75 J` |
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