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The ebullioscopic constant for benzene is `2.52 K Kg mol^(-1)`. A solution of an organic substance in benzene boils at `0.125^(@)C` higher than benzene. Calculate the molality of solution? |
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Answer» Given values are: `K_(b) = 2.52 K m^(-1)` or `2.52 K kg m^(-1)` `DeltaT_(b) = 0.125^(@)C` Using the relation,`DeltaT_(b) =K_(b)m` `:. M = (Delta_(b)T) / K_(b)` `= (0.125)/(2.52)= 0.05` Hence, molality of the solution is `0.05 m`. |
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