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The electronic configuration of an atom A is a,a+b, a+2b , a and that of B a, a + b , 3a+2b, b. (a) Write the electronic configuration of A and B. (b) Calculate their atomic numbers, (c) If the number of neutrons in A is 5b and that in B is 22.5a, calculate their mass number.

Answer» (a) The electronic configuration of A is 2,8 , 14,2 and that of B is 2,8,18,6.
(b) Their atomic number are 26 and 34 respectively .
(c) The number of neutrons in A is 5b =30 and that in B=22.5 a =45
`therefore` 34+45 =79 respectively.


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