1.

The electronic configuration (outermost ) of `Mn^(+2)` ion (atomic number of Mn=25) in its ground state isA. `3d^5 , 4s^0`B. `3d^4, 4s^1`C. `3d^3 , 4s^2`D. `3d^2, 4s^2 4p^2`

Answer» Correct Answer - A
`._25Mn=[Ar]3d^5 4s^2 underset"+2 electrons"overset"-2 electrons"hArr Mn^(2+) =[Ar]3d^5 4s^0`


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