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The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:A. `0.16`B. `0.05`C. `0.1`D. `0.2` |
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Answer» Correct Answer - A `DeltaT_(b)=(1000xx0.52xx13.44)/(134.4xx1000)xx(1+2alpha)` `:.alpha =1` `0.052xx3=0.156` |
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