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The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:A. 0.16B. 0.05C. 0.1D. 0.2 |
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Answer» Correct Answer - A Molality =`13.44/134.4=0.1` For `CuCl_(2)`,`i=3` `DeltaT_(b)=i xx K_(b) xx m` =`3 xx 0.52 xx 0.1` =`0.156^(@)` |
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