1.

The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:A. 0.16B. 0.05C. 0.1D. 0.2

Answer» Correct Answer - A
Molality =`13.44/134.4=0.1`
For `CuCl_(2)`,`i=3`
`DeltaT_(b)=i xx K_(b) xx m`
=`3 xx 0.52 xx 0.1`
=`0.156^(@)`


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