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The empty weight fraction of a jet transport with fixed sweep is given by ______(a) 1.02*(Wo^-0.06)*1.0(b) 1.5*(Wo^-0.16)*1.0(c) 1.09*(Wo^-0.06)*1.12(d) 1.02*(Wo^-0.06)*1.04This question was posed to me in a national level competition.My question comes from Conceptual Sketch Sizing in portion Conceptual Sketch Sizing of Aircraft Design

Answer»

Right option is (a) 1.02*(Wo^-0.06)*1.0

To elaborate: The design take-off GROSS weight is W0 = Wcrew + Wpayload + Wfuel + Wempty

The FUEL and empty weight are taken as fractions of gross weight and thus following is given as

Empty weight fraction= Wempty / W0 = A*K*(W0) ^c

Where, A and c are CONSTANT and dependent of type of Aircraft and K = variable sweep constant

For a TYPICAL Jet transport aircraft with FIXED sweep, A = 1.02, c = -0.06 and K = 1.0.



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